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8x^2-54x+91=0
a = 8; b = -54; c = +91;
Δ = b2-4ac
Δ = -542-4·8·91
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-2}{2*8}=\frac{52}{16} =3+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+2}{2*8}=\frac{56}{16} =3+1/2 $
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